
结果如下所示

有三种方法可以实现
方法一
SELECT ID ,Name ,
( SELECT MAX(LastUpdateDate)
FROM ( VALUES ( UpdateByApp1Date), ( UpdateByApp2Date),
( UpdateByApp3Date) ) AS UpdateDate ( LastUpdateDate )
) AS LastUpdateDate
FROM ##TestTable
方法二
SELECT ID ,[Name] ,
MAX(UpdateDate) AS LastUpdateDate
FROM ##TestTable UNPIVOT ( UpdateDate FOR DateVal IN ( UpdateByApp1Date,
UpdateByApp2Date,
UpdateByApp3Date ) ) AS u
GROUP BY ID ,
Name
方法三
SELECT ID ,name ,
( SELECT MAX(UpdateDate) AS LastUpdateDate
FROM ( SELECT tt.UpdateByApp1Date AS UpdateDate
UNION
SELECT tt.UpdateByApp2Date
UNION
SELECT tt.UpdateByApp3Date
) ud
) LastUpdateDate
FROM ##TestTable tt
第一种方法使用values子句,将每行数据构造为只有一个字段的表,以后求最大值,非常巧妙
第二种方法使用行转列经常用的UNPIVOT 关键字进行转换再显示
第三种方法跟第一种方法差不多,但是使用union将三个UpdateByAppDate字段合并为只有一个字段的结果集然后求最大值
第一种方法的执行计划

第二种方法的执行计划

第三种方法的执行计划

总的来说,第一种方法的执行计划是最好的
注意,这里不涉及分组
IF (OBJECT_ID('tempdb..##TestTable') IS NOT NULL) DROP TABLE ##TestTable CREATE TABLE ##TestTable ( ID INT IDENTITY(1, 1) PRIMARY KEY , Name NVARCHAR(40) , UpdateByApp1Date DATETIME , UpdateByApp2Date DATETIME , UpdateByApp3Date DATETIME ) INSERT INTO ##TestTable ( Name, UpdateByApp1Date, UpdateByApp2Date, UpdateByApp3Date ) VALUES ( 'ABC', '2015-08-05', '2015-08-04', '2015-08-06' ), ( 'ABC', '2015-07-05', '2015-06-04', '2015-09-06' ), ( 'NewCopmany', '2014-07-05', '2012-12-09', '2015-08-14' ), ( 'MyCompany', '2015-03-05', '2015-01-14', '2015-07-26' ) SELECT * FROM ##TestTable SELECT ID ,Name ,
( SELECT MAX(LastUpdateDate)
FROM ( VALUES ( UpdateByApp1Date), ( UpdateByApp2Date),
( UpdateByApp3Date) ) AS UpdateDate ( LastUpdateDate )
) AS LastUpdateDate
FROM ##TestTable

name列相同的话,是无法得出name分组之后的最大值,这里要注意一下